100-122k^2=0

Solution for 100-122k^2=0 equation:

100-122k^2=0

a = -122; b = 0; c = +100;
Δ = b2-4ac
Δ = 02-4·(-122)·100
Δ = 48800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48800}=\sqrt{400*122}=\sqrt{400}*\sqrt{122}=20\sqrt{122}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{122}}{2*-122}=\frac{0-20\sqrt{122}}{-244}
=-\frac{20\sqrt{122}}{-244}
=-\frac{5\sqrt{122}}{-61}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{122}}{2*-122}=\frac{0+20\sqrt{122}}{-244}
=\frac{20\sqrt{122}}{-244}
=\frac{5\sqrt{122}}{-61}
$